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A sinusoidal voltage of peak value 250V is applied to a series LCR circuit, in which R=8Ω, L=24 mH and C=60μF . The value of power dissipated at resonant condition is ‘x’ kW.The value of x to the nearest integer is……………...

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answer is 4.

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Detailed Solution

At resonance , XL=XC Hence, impedance, Z = R Power = Vrmsirms=Vrms2R=2502 2502 ×18 =3.906 kW

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