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Equilibrium of a particle

Question

The situation shown in the figure, all surfaces are frictionless. Masses of blocks B and C are 1 kg and 2kg, respectively. Find the mass of the blocks A for which the
block B remains stationary with respect to block C.

Moderate
Solution

Taking blocks B and C as a system, Nsin30=mB+mCa0
(leftward).
Here, N is normal reaction between A and C.

From free body diagram of block B in the frame of block C.

    mBgsin30=mBa0cos30     a0=103m/s2

From free body diagram of block A in the frame of block C

N+mAa0sin30=mAgcos30or  mB+mCa0sin30+mAa0sin30=mAgcos30or  3×103×2+mA×1023=mA×10×32mA=6kg



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