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Q.

For the situation as shown in the figure, find the velocity of image formed by the mirror

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a

10 cms−1in the direction of velocity of lens

b

10 cms−1in the opposite direction of velocity of lens

c

Zero

d

20 cms−1in the direction of velocity of object

answer is B.

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Detailed Solution

For first refraction through lens,  u=−30cm,f=+20cm ∵1v−1u=1f ∴v=+60cm vimage lens=v2u2dudt=602−3026−2Or    vimage−vlens=16cms−1 ∴vimage=16+2=18 cms−1Image formed by lens will act as object  for the mirror hence the object distance for the mirror is equal to u 'For reflection through mirror,  u'=−(80-60)=-20cm,f'=−10cm ∴v'=−20cm ∴vimage mirror=−−202−20218−4=−14cms−1 ∴vimage =−14+4=−10cms−1
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