For the situation as shown in the figure, find the velocity of image formed by the mirror
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a
10 cms−1in the direction of velocity of lens
b
10 cms−1in the opposite direction of velocity of lens
c
Zero
d
20 cms−1in the direction of velocity of object
answer is B.
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Detailed Solution
For first refraction through lens, u=−30cm,f=+20cm ∵1v−1u=1f ∴v=+60cm vimage lens=v2u2dudt=602−3026−2Or vimage−vlens=16cms−1 ∴vimage=16+2=18 cms−1Image formed by lens will act as object for the mirror hence the object distance for the mirror is equal to u 'For reflection through mirror, u'=−(80-60)=-20cm,f'=−10cm ∴v'=−20cm ∴vimage mirror=−−202−20218−4=−14cms−1 ∴vimage =−14+4=−10cms−1