First slide

Application of Newtons laws

Question

In the situation as shown in figure if acceleration of B is a then find the acceleration of A (B always remains horizontal)

Moderate

A

$asin θ$
B

$acot θ$
C

$2a \tan θ$
D

$2 acos θ$

Solution

Components of accelerations of A and B along normal $(\hat{n})$ to the incline of wedge should be same.
$\begin{array}{l} \Rightarrow A \sin θ = a \cos (2 θ - 90^{\circ}) \\ \Rightarrow A \sin θ = a \sin 2 θ \\ \Rightarrow A = 2 a \cos θ \end{array}$

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