Six particles situated at the corners of a regular hexagon of side d move at a constant speed v. Each particle maintains a direction towards the particle at the next corner. The time of the particles will take to meet each other.
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a
2d/3v
b
2d/v
c
3d/2v
d
4d/3v
answer is B.
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Detailed Solution
The particles will meet at the centre of the hexagon whose distance from point A id d. Therefore t =Displacement of any particle v cos 600 ⇒t=dv/2=2dv