Six similar bulbs are connected as shown in the figure with a DC source of emf E, and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) in the situation when two from section A and one from section B are glowing, will be
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a
2 : 1
b
4 : 9
c
9 : 4
d
1 : 2
answer is B.
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Detailed Solution
Power consumed, P=i2R Peq1=(i/3)2×3R+(i/3)2×3R=23i2R ......(i) (ii) Peq2=(i/2)2×R+(i/2)2R+i2R =32i2R .........(ii) Divide equation (i) by (ii), we get Peq1Peq2=23i2R32i2R=49