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A slit is illuminated by red light of wavelength 6500A0 . The first minimum is obtained atθ=300 . The width of the slit is

a
3200 A0
b
1.24  micron
c
6.5×10−4mm
d
2.6×10−4cm

detailed solution

Correct option is B

Wavelength λ=6500 A0=6500×10−10 m Angular fringe width θ=300 Width of the slit a=?          a=λθ ⇒  a=6500×10−10(π6) ⇒  a=1.24×10−6m ⇒  a=1.24 micron

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