A slit is illuminated by red light of wavelength 6500 A0 . The first minimum is obtained atθ=300 . The width of the slit is

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3200 A0

1.24 micron

6.5×10−4mm

2.6×10−4cm

answer is B.

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Detailed Solution

Wavelength λ=6500 A0=6500×10−10 m Angular fringe width θ=300 Width of the slit a=? a=λθ ⇒ a=6500×10−10(π6) ⇒ a=1.24×10−6m ⇒ a=1.24 micron

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