First slide

Diffraction of light-Wave Optics

Question

A slit of size 0.15 cm is placed at 2.1 m from a screen. On illuminated it by a light of wavelength 5 $\times$ 10^–5cm. The width of central maxima will be

Moderate

A

70 mm
B

0.14 mm
C

1.4 mm
D

0.14 cm

Solution

$Width of central maxima = \frac{2 λD}{d} = \frac{2 \times 2 .1 \times 5 \times 10^{- 7}}{0 .15 \times 10^{- 2}} = 1 .4 \times 10^{- 3} m = 1 .4 mm$

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