First slide

Diffraction

Question

A slit of size 0.15 cm is placed at 2.1 m from a screen. On illuminated it by a light of wavelength $5 \times 10^{- 5} cm$ . The width of central maxima will be

Easy

A

70 mm
B

0.14 mm
C

1.4 mm
D

0.14 cm

Solution

Width of central maxima $= \frac{2 λ D}{d}$
$= \frac{2 \times 2.1 \times 5 \times 10^{- 7}}{0.15 \times 10^{- 2}} = 1.4 \times 10^{- 3} m = 1.4 mm$

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