A slit (wavelength λ=600nm) of adjustable width is used to illuminate two points 0.1 mm apart. Initially, the slit is closed and then gradually it is opened. The width at which the fringes on a screen 2 m apart will just disappear is
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a
1 mm
b
2 mm
c
10 mm
d
12 mm
answer is D.
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Detailed Solution
The required angular width is ϕ=λd or bD=λd ∴d=600×10−90.1×10−3×2=12×10−3m=12 mm