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The slope of the graph drawn between stopping potential and frequency of incident radiation will be
detailed solution
Correct option is A
eV= h(ν - νo)V= he(v-vo)slope= h/eTalk to our academic expert!
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The work functions of three metals A,B and C are WA, WB and WC respectively. They are in the decreasing order. The correct graph between stopping potential V0 and frequency V of incident radiation is
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