A small amount of mercury ‘Hg’ is taken in a container such that its expansion is equal to expansion of container made of glass then γHg=x¯ γg . Where x= (γHg is coefficient of volume expansion of mercury;γg coefficient of volume expansion of glass)

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Detailed Solution

if γHg is coefficient of volume expansion of mercury;γg coefficient of volume expansion of glass then practically found relation is γHg =7γg

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