A small amount of mercury ‘Hg’ is taken in a container such that its expansion is equal to expansion of container made of glass then γHg=x¯ γg . Where x=
(γHg is coefficient of volume expansion of mercury;γg coefficient of volume expansion of glass)
7
17
5
15
if γHg is coefficient of volume expansion of mercury;γg coefficient of volume expansion of glass then practically found relation is γHg =7γg