A small ball of density ρ is immersed in a liquid of density σ(>ρ) to a depth h and released. The height above the surface of water up to which the ball will jump is

Let V be the volume of the ball.Net upward force=Vσg−VρgNet upward acceleration,a=Vσg−VρgVρ=(σ−ρ)gρ Velocity at the surface =2(σ−ρ)ghρIf ha is the height in air to which the ball rises, then0−2(σ−ρ)ghρ=2(−g)ha∴ ha=(σ−r)ghgρ=σρ−1h