A small ball of density r is immersed in a liquid of density σ(> ρ) to a depth h and released. The height above the surface of water upto which the ball will jump is

Let V be the volume of the ball.Net upward force = Vσg-VρgNet upward acceleration,a = Vσg-VρgVρ = (σ-ρ)gρVelocity at the surface = 2(σ-ρ)ghρIf ha is the height in air to which the ball rises, then 0 -2(σ-ρ)ghρ = 2(-g)haha = (σ-r)ghgρ = (σρ-1)h