A small ball of mass m is thrown upward with velocity u from the ground. The ball experiences a resistive force mkν2 where ν is its speed. The maximum height attained by the ball is:
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a
12ktan−1ku2g
b
1kln1+ku22g
c
12kln1+ku2g
d
1ktan−1ku22g
answer is C.
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Detailed Solution
Fnet=-mg-mkv2 [Both gravity and resistive force decelerate the ball]⇒vdvdy=-g-kv2 ⇒∫u0vdvg+kv2=-∫0Hdy⇒H=12kln1+ku2 g