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Q.

A small bar magnet has a magnetic moment 1.2 Am2. The magnetic field at a distance 0.1m on its axis will be μ0=4π x 10-7 T-m/A

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a

1.2 x 10-4 T

b

2.4 x 10-4T

c

2.4 x 104 T

d

1.2 x 104 T

answer is B.

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Detailed Solution

B=μ04π.2Md3⇒B=10-7 x 2 x 1.20.13=2.4 x 10-4 T
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