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A small bar magnet has a magnetic moment $1.2 {Am}^{2}$ . The magnetic field at a distance 0.1m on its axis will be $(μ_{0} = 4 π x 10^{- 7} T - m / A)$

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1.2 x 10-4 T

2.4 x 10-4T

2.4 x 104 T

1.2 x 104 T

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detailed solution

Correct option is B

B=μ04π.2Md3⇒B=10-7 x 2 x 1.20.13=2.4 x 10-4 T

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A small bar magnet has a magnetic moment 1.2 Am2. The magnetic field at a distance 0.1m on its axis will be μ0=4π x 10-7 T-m/A

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A small bar magnet has a magnetic moment $1.2 {Am}^{2}$ . The magnetic field at a distance 0.1m on its axis will be $(μ_{0} = 4 π x 10^{- 7} T - m / A)$