A small bar magnet A oscillates in a horizontal plane with a period T at a place where the angle of dip is 60o. When the same needle is made to oscillate in a vertical plane coinciding with the magnetic meridian, its period will be

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2 T

answer is A.

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Detailed Solution

T=2πIMB⇒TT'=B'B=BBH⇒TT'=1cosϕ=1cos60o=2⇒T'=T2

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