A small bead of mass m moving with velocity v gets threaded on a stationary semicircular ring of mass m and radius R kept on a horizontal table. The ring can freelyrotate about its center The bead comes to rest relative to the ring. What will be the final angular velocity of the system?

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2vR

v2R

3vR

answer is C.

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Detailed Solution

Using conversation of angular momentum about O, we get Li=Lf ⇒mvR=mR2+mR2ω ⇒ω=v2R

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