A small block of mass $$0$$⋅$$1$$ kg is pressed against a horizontal spring fixed at one end to compress the spring through $$5$$⋅$$0$$ cm as shown in figure.The spring constant is $$100$$ $$N/m$$. When released the block moves horizontally till it leaves the spring. Where will it hit the ground $$2$$ m below the spring ?

Question

Infinity Learn · Accepted Answer

The energy stored in spring will be given to mass as kinetic energy. $$Hence12kx2=12mv212$$×$$100$$×$$51002=12$$×$$0$$⋅$$1$$×$$v2Solving$$, we get            $$V=(5/2)Now$$        $$y=2=0+12gt2or$$       $$t=(4/g)=(2/5)Further$$,        $$X=Vt=52$$×$$25=1m$$

A small block of mass 0⋅1 kg is pressed against a horizontal spring fixed at one end to compress the spring through 5⋅0 cm as shown in figure.
The spring constant is 100 N/m. When released the block moves horizontally till it leaves the spring. Where will it hit the ground 2 m below the spring ?

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A small block of mass 0⋅1 kg is pressed against a horizontal spring fixed at one end to compress the spring through 5⋅0 cm as shown in figure.The spring constant is 100 N/m. When released the block moves horizontally till it leaves the spring. Where will it hit the ground 2 m below the spring ?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

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