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Q.

A small block of mass1 kg starts moving with constant velocity 2 m/s on a smooth long plank of mass 10 kg which is also pulled by a horizontal force F = 10 t where t is in seconds and F in Newton's (the initial velocity of the plank is zero)Displacement of 1 kg block with respect to plank at the instant when both have same velocity isThe time (t≠0) at which displacement of block and plank with respect to ground is same will beRelative velocity of plank with respect to block when acceleration of plank is 4 m/s2 will be

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a

443m

b

4 m

c

83m

d

2 m

e

2 s

f

23s

g

33s

h

4 s

answer is , , .

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Detailed Solution

Acceleration of 10 kg plank,                       a=Fm=10t10=t∴   dv=adtor   ∫0v dv=∫0t tdtor   v=t22or    t=2s when v=2m/s       s1=vt=2×2=4m           = displacement of 1kg       s2=∫0t vdt=∫0t t22dt=t36At  t=2s                      s2=(2)36=43m   ∴              s12=s1−s2=4−43=83ms1=s2  or  2t=t36∴ t=23sa=t∴ a=4ms2 at t=4s         vPB=vP−vB        =t22−2        =6m/s     (at = 4s)
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