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Q.

A small block of mass m, charge +q is kept at the top of a smooth inclined plane of angle 30° placed in an elevator moving upward with an acceleration a0. Electric field E exits between the vertical side walls of the elevator. The time taken by the block to come to the lowest point of inclined plane is ( assuming the surface to be smooth).

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a

t=2hg

b

t=2hg-a0+qEm

c

t=22hg+a0-3qEm

d

t=2hg+a02-qEmh2

answer is C.

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Detailed Solution

Net acceleration of block down the incline isa=g+a02-qE32m ⇒a=12g +a0-qE3m Now, hsin 30=12at2 ⇒2h=14g+a0-3qEmt2 ⇒t=8hg+a0-qEm3 ⇒t=22hg+a0-qEm3
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A small block of mass m, charge +q is kept at the top of a smooth inclined plane of angle 30° placed in an elevator moving upward with an acceleration a0. Electric field E exits between the vertical side walls of the elevator. The time taken by the block to come to the lowest point of inclined plane is ( assuming the surface to be smooth).