First slide
Work done by Diff type of forces
Question

A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator. The elevator goes up with a uniform velocity v and the block does not slide on the wedge. The work done by the force of friction on the block in a time t will be

Moderate
Solution

As block does not side,  Hence, force of friction.

f=mgsinθ

In time t, displacement,  s=νt

 Wf=f·s·cos90°-θ = μmg sin θ .vt .sin θ = μmgvt sin2 θ

 

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