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A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator. The elevator goes up with a uniform velocity v and the block does not slide on the wedge. The work done by the force of friction on the block in a time t will be

a
zero
b
mgvt cos2θ
c
mgvt  sin2θ
d
12mgvt  sin 2θ

detailed solution

Correct option is C

As block does not side,  Hence, force of friction.f=mgsinθIn time t, displacement,  s=νt∴ Wf=f·s·cos90°-θ = μmg sin θ .vt .sin θ = μmgvt sin2 θ

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