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Q.

A small block of mass m slides on a frictionless horizontal table. It is constrained to move inside a ring of radius l which is fixed to the table. At t = 0, the block has a tangential velocity v0. The coefficient of friction between the block and the ring is μ. The velocity of the block at time t is

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a

v01+μv0tl

b

v01+2μv0tl

c

v01−μv0tl

d

v0μv0tl

answer is A.

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Detailed Solution

Suppose velocity at an instant is y. Then N=mv2r …….(i)and −μN=mdvdt……..(ii)From Eqs. (i) and (ii), −μv2r=dvdt∫v0v dvv2=-μr∫0t dtOn solving we get v at time t.-1vv0v=-μtrv=v01+μv0tl  substituting r=l
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