A small block slides without friction down an inclined plane starting from rest. Let Sn be the distance travelled from time t = n -1 to t = n. Then [Sn/(Sn+1)] is

The displacement from  t = n - 1 tot = n is given by∴Snth=a2(2n−1)The body starts from rest, i.e., u = 0∴Snth=a2(2n−1)Then SnSn+1=a2(2n−1)a2[2(n+1)−1]=(2n−1)(2n+1)