Q.

small block of wood of relative density 0.5 is submerged in water at a depth of 5m. When the block is released, it starts moving upwards, the acceleration of the block is (g = 10 ms-2)

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a

5ms-2

b

10ms-2

c

7.5ms-2

d

15ms-2

answer is B.

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Detailed Solution

maappareat = force of buoancy -weight of body =Vdwg−VdBg⇒aapparent =VdWg−VdBgVdB=gdWdB−1

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small block of wood of relative density 0.5 is submerged in water at a depth of 5m. When the block is released, it starts moving upwards, the acceleration of the block is (g = 10 ms-2)