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Conservation of mechanical energy

Question

A small bob tied at one end of a thin string of length 1 m is describing a vertical circle so that the maximum and minimum tension in the string are in the ratio 5:1. The velocity of the bob at the highest position is_________ m/s. (Take g=10m/s2)

Difficult
Solution

At bottom, let say speed is v

Tmax=mv2L+mg

As bob goes up, its speed decreases to u

Loss in KE = Gain in PE

12mv212mu2=mg(2L)u2=v24gL At top, tension is minimum, Tmin=mu2Lmg=mv24gLLmg=mv2L5mg

 Given :TmaxTmin=51mv2L+mgmv2L5mg=51v2=132gL Thus, u2=v24gL=132gL4gL=52gLu=5×10×12=5m/s



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