First slide

Simple hormonic motion

Question

A small body of mass 1 kg is executing SHM with amplitude 0.1 m and period 0.4 s. The maximum force acting on the body is:

Easy

A

12.25 N
B

24.65 N
C

34.75 N
D

44.75 N

Solution

$f_{\max} = {ma}_{\max} = {mω}^{2} A = 1 \times \frac{4 \times {(3.14)}^{2}}{{(0.4)}^{2}} \times 0.1 = 24.65 N$

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