Projection Under uniform Acceleration
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80k UsersA small body is projected horizontally from the top of a tower of height h with velocity 30 m/s. When the body is at a height h/2 above the ground its velocity vector makes an angle of with horizontal. Then h is equal to (Take )
At a height h/2 above the ground horizontal component of velocity
Vertical component of velocity
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A body of mass 1 kg is moving along positive x-axis with velocity 2 m/s. At t = 0, a constant force, parallel to positive y-axis, starts acting on the body and after 5 sec, speed of the body is found to be 4 m/s. Then work done by the force in 5 sec is
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