A small body is projected vertically upward from a point on the ground with a velocity of 50 m/s. The body arrives at the ground with a velocity of 40 m/s. If the mass of the body is 1 kg and g=10 m/s2, the average resistance force offered by air to the motion of the body is
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answer is 3.
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Detailed Solution
If R be the average air drag and H be the maximum height attained by the body, then 12mu2=mgH+RH .......(1)12mv2=mgH-RH .......(2)∴u2v2=mg+Rmg-R⇒R=mg(u2-v2)(u2+v2)=1 x 10 x (502-402)(502+402)N=9041N