A small body is projected vertically upward from a point on the ground with a velocity of $$50$$ $$m/s$$. The body arrives at the ground with a velocity of $$40$$ $$m/s$$. If the mass of the body is $$1$$ kg and $$g=10$$ $$m/s2$$, the average resistance force offered by air to the motion of the body is

Question

A small body is projected vertically upward from a point on the ground with a velocity of $$50$$ $$m/s$$. The body arrives at the ground with a velocity of $$40$$ $$m/s$$. If the mass of the body is $$1$$ kg and $$g=10$$ $$m/s2$$, the average resistance force offered by air to the motion of the body is

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If R be the average air drag and H be the maximum height attained by the body, then $$12mu2=mgH+RH$$   .......(1)12mv2=mgH-RH$$   .......$$(2)∴$$u2v2=mg+Rmg-R$$⇒$$R=mg(u2-v2)(u2+v2)=1$$ x $$10$$ x $$(502-402)(502+402)N=9041N$$

Work Energy Theorem

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A small body is projected vertically upward from a point on the ground with a velocity of 50 m/s. The body arrives at the ground with a velocity of 40 m/s. If the mass of the body is 1 kg and g $= 10 m / s^{2}$ , the average resistance force offered by air to the motion of the body is

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Work Energy Theorem

Remember concepts with our Masterclasses.

A small body is projected vertically upward from a point on the ground with a velocity of 50 m/s. The body arrives at the ground with a velocity of 40 m/s. If the mass of the body is 1 kg and g=10 m/s2, the average resistance force offered by air to the motion of the body is

If R be the average air drag and H be the maximum height attained by the body, then 12mu2=mgH+RH .......(1)12mv2=mgH-RH .......(2)∴u2v2=mg+Rmg-R⇒R=mg(u2-v2)(u2+v2)=1 x 10 x (502-402)(502+402)N=9041N

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free study material

A small body is projected vertically upward from a point on the ground with a velocity of 50 m/s. The body arrives at the ground with a velocity of 40 m/s. If the mass of the body is 1 kg and g $= 10 m / s^{2}$ , the average resistance force offered by air to the motion of the body is