Questions
A small body is projected vertically upwards from ground with velocity 30 m/s. Then the distance covered by the body in the last two seconds of its fall.
detailed solution
Correct option is B
From symmetry of vertical motion, distance covered in last two seconds = Distance covered in first two seconds =30 x 2-12 x 10 x (2)2 m=40 mTalk to our academic expert!
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