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Q.

A small body is projected vertically upwards from ground with velocity 30 m/s. Then the distance covered by the body in the last two seconds of its fall.

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a

50 m

b

40 m

c

60 m

d

20 m

answer is B.

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Detailed Solution

From symmetry of vertical motion, distance covered in last two seconds = Distance covered in first two seconds                                                            =30 x 2-12 x 10 x (2)2 m=40 m
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