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A small body is projected with a velocity of 30 m/s from a point P on an inclined plane having inclination of with horizontal in a direction perpendicular to the plane as shown in the figure. Then distance of the point Q from the point of projection P where the body will strike. The inclined plane is
detailed solution
Correct option is B
Time of flight T=2ugcos30o⇒T=2 x 3010 x 3/2sec=43sec∴PQ=12 x g sinα x T2=12 x 10 sin 30o x (43)2m=120 mTalk to our academic expert!
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