Questions
A small circular ring of radius 1 cm is carrying a current of 10A. P is point on the axis of the ring at a distance of 1m from its centre. Then magnitude induction at P is
a
π50μT
b
π100μT
c
π500μT
d
π5000μT
detailed solution
Correct option is D
M=Magnetic dipole moment of the ring=π×(10−2)2×10A−m2=π×10−3A−m2∴B=μ04π.2Mx3=10−7×2×π×10−313T=π5000μTTalk to our academic expert!
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A circular loop has a radius of 5 cm and it is carrying a current of 0.1 A. Its magnetic moment is
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