First slide

Magnetic Dipole moment

Question

A small circular ring of radius 1 cm is carrying a current of 10A. P is point on the axis of the ring at a distance of 1m from its centre. Then magnitude induction at P is

Easy

A

$\frac{π}{50} μT$
B

$\frac{π}{100} μT$
C

$\frac{π}{500} μT$
D

$\frac{π}{5000} μT$

Solution

M=Magnetic dipole moment of the ring $= π \times {(10^{- 2})}^{2} \times 10 A - m^{2} = π \times 10^{- 3} A - m^{2}$
$∴ B = \frac{μ_{0}}{4 π} . \frac{2 M}{x^{3}} = 10^{- 7} \times \frac{2 \times π \times 10^{- 3}}{{(1)}^{3}} T = \frac{π}{5000} μT$

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