Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A small circular ring of radius 1 cm is carrying a current of 10A. P is point on the axis of the ring at a distance of 1m from its centre. Then magnitude induction at P is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

π50μT

b

π100μT

c

π500μT

d

π5000μT

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

M=Magnetic  dipole moment of the ring=π×(10−2)2×10A−m2=π×10−3A−m2∴B=μ04π.2Mx3=10−7×2×π×10−313T=π5000μT
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
A small circular ring of radius 1 cm is carrying a current of 10A. P is point on the axis of the ring at a distance of 1m from its centre. Then magnitude induction at P is