A small coil of $$10$$ turns is placed inside a solenoid of length $$20$$ cm and $$240$$ turns carry a current of $$10$$π A The area of small coil is $$2.5$$ $$cm2$$ and resistance $$4.8$$ Ω then the current reduces to zero in $$25$$ ms, the value of average induced current is :

Question

A small coil of $$10$$ turns is placed inside a solenoid of length $$20$$ cm and $$240$$ turns carry a current of $$10$$π A The area of small coil is $$2.5$$ $$cm2$$ and resistance $$4.8$$ Ω then the current reduces to zero in $$25$$ ms, the value of average induced current is :

Infinity Learn · Accepted Answer

Values given for coil :Number of turns of small coil $$=$$ $$10Area$$ of $$coil=$$ $$2.5$$ $$cm2$$ $$=$$ $$2.5$$ x $$10-4m2$$∆$$t=25$$ x $$10-3sValues$$ given for solenoidI $$=$$ $$20$$ x $$10-2$$ m, N $$=$$ $$240I=10$$π amp, $$n=24020$$ x $$10-2=12$$ x $$102According$$ to Faraday's law, induced emf $$E=-d$$ϕdtInduced emf in coil :$$I=-d$$ϕ$$dtR=(NBA)/$$ $$dtR=$$μ$$0nINA$$∆tR  $$=10$$ x $$4$$π x $$10-7$$ x $$12$$ x $$102$$ x $$10/$$π x $$2.5$$ x $$10-425$$ x $$10-3$$ x $$4.8$$ $$=4$$ x $$12$$ x $$10-7$$ x $$102$$ x $$10$$ x $$10-410-3$$ x $$4.8=10-4$$ $$I=0.1$$ mA

A small coil of 10 turns is placed inside a solenoid of length 20 cm and 240 turns carry a current of $\frac{10}{π}$ A The area of small coil is 2.5 cm² and resistance 4.8 $Ω$ then the current reduces to zero in 25 ms, the value of average induced current is :

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A small coil of 10 turns is placed inside a solenoid of length 20 cm and 240 turns carry a current of 10π A The area of small coil is 2.5 cm2 and resistance 4.8 Ω then the current reduces to zero in 25 ms, the value of average induced current is :

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A small coil of 10 turns is placed inside a solenoid of length 20 cm and 240 turns carry a current of $\frac{10}{π}$ A The area of small coil is 2.5 cm² and resistance 4.8 $Ω$ then the current reduces to zero in 25 ms, the value of average induced current is :