A small electric dipole is of dipole moment p. The electric potential at a distance ‘r’ from its centre and making an angle θ from the axis of dipole will be:
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a
kpsinθr2
b
kpcosθr2
c
kpr31+3cos2θ
d
kpr31+3sin2θ
answer is B.
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Detailed Solution
Potential at D VD=kqBD−kqADBD=r−acosθ,AD=r+acosθVD=kqr−acosθ−kqr+acosθ use (r>>acosθ,&P=q⋅2a)⇒VD=kq(2acosθ)r2=kpcosθr2