Questions
A small electric dipole is placed at origin with its electric dipole moment vector acting along positive x-axis. Direction of electric field intensity vector at a point (2m, , 0) is
detailed solution
Correct option is A
tanθ=222=2tanα=12tanθ=22=12Angle made by E with X axis is θ+α=tan-12+tan-112=54.73°+35.27°=90° with X axis E is along Y axis
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