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A small electric dipole is placed at origin with its electric dipole moment vector acting along positive x-axis. Direction of electric field intensity vector at a point (2m, 22m , 0) is Take θ=tan-12=54.73° and θ=tan-112=35.27°

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a
directed along +y axis
b
directed along - y axis
c
directed along +z axis
d
directed along -x axis

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detailed solution

Correct option is A

tanθ=222=2tanα=12tanθ=22=12Angle made by E with X axis is θ+α=tan-12+tan-112=54.73°+35.27°=90° with X axis  E is along Y axis

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