A small hole of area of cross-section 2 mm2 is present near the bottom of a fully filled open tank of height 2 m. Taking g=10 m/s2 the rate of flow of water through the open hole would be nearly

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6.4×10-6 m3/s

12.6×10-6 m3/s

8.9×10-6 m3/s

2.23×10-6 m3/s

answer is B.

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Detailed Solution

According to Torricelli's theorem, Velocity, v=2gh=2×10×2=6.32 m/s Volume of liquid flowing per second, Q=Av =2×10-6×6.32=12.6×10-6 m3/s

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