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A small hole of area of cross-section $2 {mm}^{2}$ is present near the bottom of a fully filled open tank of height 2 m. Taking $g = 10 m / s^{2}$ the rate of flow of water through the open hole would be nearly

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6.4×10-6 m3/s

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2.23×10-6 m3/s

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detailed solution

Correct option is B

According to Torricelli's theorem, Velocity, v=2gh=2×10×2=6.32 m/s Volume of liquid flowing per second, Q=Av =2×10-6×6.32=12.6×10-6 m3/s

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A small hole of area of cross-section 2 mm2 is present near the bottom of a fully filled open tank of height 2 m. Taking g=10 m/s2 the rate of flow of water through the open hole would be nearly

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Ready to Test Your Skills?

free study material

A small hole of area of cross-section $2 {mm}^{2}$ is present near the bottom of a fully filled open tank of height 2 m. Taking $g = 10 m / s^{2}$ the rate of flow of water through the open hole would be nearly