Questions
A small iron ball falls through a viscous liquid at a constant speed of 20cm/sec. If the steel ball is pulled upwards with a force equal to twice its effective weight, how will it move upward?
detailed solution
Correct option is C
For the first case, B+6πηrv=mgFor the second case, F+B=mg+6πηrvt2mg−2B+B=mg+6πηrvt⇒mg−B=6πηrvtSolving we get, v= 20 cm/secTalk to our academic expert!
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The terminal velocity of a small sized spherical body of radius r falling vertically in a viscous liquid is given by the following proportionality :
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