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Q.

A small iron ball falls through a viscous liquid at a constant speed of 20cm/sec. If the steel ball is pulled upwards with a force equal to twice its effective weight, how will it move upward?

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a

with constantly increasing speed

b

with constantly decreasing speed

c

with the same speed

d

will be at rest without any movement

answer is C.

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Detailed Solution

For the first case,  B+6πηrv=mgFor the second case,  F+B=mg+6πηrvt2mg−2B+B=mg+6πηrvt⇒mg−B=6πηrvtSolving we get, v= 20 cm/sec
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A small iron ball falls through a viscous liquid at a constant speed of 20cm/sec. If the steel ball is pulled upwards with a force equal to twice its effective weight, how will it move upward?