A small metallic ring of radius r (r <<< d) is made to move with velocity V towards an infinitely long current carrying conductor AB and the current induced in the ring is found to be 2 mA. If the same ring is made to move towards the same current carrying conductor AB with velocity 2V as shown in figure - (2), then induced current in the ring is
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a
1 mA, anticlockwise
b
3 mA, clockwise
c
2 mA, anticlockwise
d
23 mA, clockwise
answer is C.
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Detailed Solution
For the component of velocity 2Vcos30o, no emf is induced in the ring and emf is induced in the ring due to the component 2Vsin30o. Also rate of change of flux is directly proportional to the velocity of the ring. Hence we can write, i2i1=2Vsin30oV⇒i2=i1=2mA