Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A small metallic ring of radius r (r <<< d) is made to move with velocity V towards an infinitely long current carrying conductor AB and the current induced in the ring is found to be 2 mA. If the same ring is made to move towards the same current carrying conductor AB with velocity 2V as shown in figure - (2), then induced current in the ring is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

1 mA, anticlockwise

b

3 mA, clockwise

c

2 mA, anticlockwise

d

23 mA, clockwise

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

For the component of velocity 2Vcos30o, no emf is induced in the ring and emf is induced in the ring due to the component 2Vsin30o. Also rate of change of flux is directly proportional to the velocity of the ring. Hence we can write, i2i1=2Vsin30oV⇒i2=i1=2mA
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring