First slide

Motional EMF

Question

A small metallic ring of radius r (r <<< d) is made to move with velocity V towards an infinitely long current carrying conductor AB and the current induced in the ring is found to be 2 mA. If the same ring is made to move towards the same current carrying conductor AB with velocity 2V as shown in figure - (2), then induced current in the ring is
Figure (1) and (2)

Moderate

A

1 mA, anticlockwise
B

$\sqrt{3} mA$ , clockwise
C

2 mA, anticlockwise
D

$2 \sqrt{3} mA$ , clockwise

Solution

For the component of velocity $2 Vcos 30^{o}$ , no emf is induced in the ring and emf is induced in the ring due to the component $2 Vsin 30^{o}$ . Also rate of change of flux is directly proportional to the velocity of the ring. Hence we can write,
$\frac{i_{2}}{i_{1}} = \frac{2 V \sin 30^{o}}{V} \Rightarrow i_{2} = i_{1} = 2 mA$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App