A small object is projected horizontally from the top of a tower of height 40 m with a velocity of 10 m/s. Simultaneously another small object is projected from the base of the tower with a velocity of 20 m/s making an angle θ with horizontal in the same plane. If the objects collide at a point at time t, find t.

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answer is 2.

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Detailed Solution

h1+h2=4012 gt2+usinθ.t−12 gt2=H⇒ t=Hu sinθ=4020sinθ=2sinθAgain, 10 × t=20 cosθ × t ⇒ θ=600∴ t=2sin 600 = 43 sec

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