A small piece of metal wire is dragged across the gap between the poles of a magnet in 0.4 sec. If the change in magnetic flux is 8 x 10-4 Wb, emf induced in the wire is :

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8 X 10-3 V

6 X 10-3 V

4 X 10-3 V

2 X 10-3 V

answer is D.

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Detailed Solution

emf induced= dϕdt= 8×10-40.4= 2×10-3 V

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