A small piece of wire bent into an L shape, with upright and horizontal portions of equal lengths, is placed with the horizontal portion along the axis of the concave mirror whose radius of curvature is $$10$$ cm. If the bend is $$20$$ cm from the pole of the mirror, then the ratio of the lengths of the images of the upright and horizontal portions of the wire is

Question

Infinity Learn · Accepted Answer

For concave mirror, focal length $$=R2=102For$$ upright portion, Transverse Magnification $$m=ff$$−$$u=$$−$$102$$−$$102$$−−$$20=$$−$$5$$−$$5+20=$$−$$515=$$−$$13For$$ horizontal portion, for small size objects,  Longitudinal magnification is  $$=$$ $$vu2$$ $$=$$ $$132i$$.e.,  $$19Required$$ ratio is  −$$1/31/9=$$−$$3$$:$$1$$

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