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A small piece of wire bent into an L shape, with upright and horizontal portions of equal lengths, is placed with the horizontal portion along the axis of the concave mirror whose radius of curvature is 10 cm. If the bend is 20 cm from the pole of the mirror, then the ratio of the lengths of the images of the upright and horizontal portions of the wire is

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a
1 : 2
b
3 : 1
c
3 : 2
d
2 : 1

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detailed solution

Correct option is B

Given, u=−20 ; f=−5. From mirror formula we will get v= -203cm.Magnification = -vu=-13and lateral magnification f2(u-f)2=19. So the required ratio will become 3 : 1


Similar Questions

A convex lens is at a distance of 10 cm from a convex mirror of focal length 10 cm as shown in figure. A beam of light parallel to the principal axis is incident on the tens. After refraction through the lens, reflection at the mirror and again refraction through the lens, the final emergent beam refraces the path of the incident beam then focal length of the lens is 


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