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Q.

A small solid ball is dropped from a height above the free surface of a liquid. It strikes the surface of the liquid at t = 0. The density of the material of the ball is 500 kg/m3 and that of liquid is 1000 kg/m3. If the ball comes momentarily at rest at t = 2 sec then initial height of the ball from surface of liquid was (neglect viscosity):

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a

20 m

b

10 m

c

15 m

d

25 m

answer is A.

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Detailed Solution

Velocity of ball when it reaches to surface of liquida = 1000 gV-500 gV500 V; where V is the volume of the ball.a =10 m/sec2Apply v = u + at ⇒0 = 2gh -10t⇒2gh = 10×(2)⇒2×10×h = 400 ⇒ 20 m
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