A small sphere is given vertical velocity of magnitude v0=5ms−1 and it swings in a vertical plane about the end of a massless string. The angle θ with the vertical at which string will break, knowing that it can withstand a maximum tension equal to twice the weight of the sphere, is
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a
cos−123
b
cos−114
c
60∘
d
30∘
answer is B.
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Detailed Solution
v2=v02+2glcosθT=mgcosθ+mv2l Given T=2mg2mg=mgcosθ+mlv02+2glcosθ⇒ cosθ=14