A small sphere of mass m is tied to one end of a string of length l. The other end of the string is attached to a fixed point o . The sphere is released from position A when the string is horizontal and the sphere starts moving in a vertical circle. When the string makes an angle of θ with horizontal, centripetal acceleration of the sphere is,
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a
2g sin θ
b
g cos θ
c
g sin θ
d
2gcos θ
answer is A.
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Detailed Solution
If V be the speed of the sphere at position B,Then conserving energy, 12mv2=mglsinθ⇒v2l=2gsinθ∴Centripetal acceleration at B, an=v2l=2gsinθ