Questions
A small sphere is suspended by a string of length m. If the sphere rotates in a horizontal circle of radius 2m with uniform speed, the time period of rotation of the sphere is
detailed solution
Correct option is B
Tsinθ=mω2r=mω2(lsinθ)⇒T=mω2l.......(1)Also, Tcosθ=mg.......(2)∴ ω2lcosθ=g⇒ω=glcosθ∴ Time period of rotation, T1=2π10=2π2×cos60o10sec=2π110secTalk to our academic expert!
Similar Questions
A string of length l = 1 m is fixed at one end and carries a mass of 100 gm at other end. The string makes revolution per second about a vertical axis passing through its second end. What is the angle of inclination of the string with the vertical?
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