A small sphere is suspended by a string of length 3m. If the sphere rotates in a horizontal circle of radius 2m with uniform speed, the time period of rotation of the sphere is
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a
π5sec
b
2π10sec
c
2π5sec
d
π10sec
answer is B.
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Detailed Solution
Tsinθ=mω2r=mω2(lsinθ)⇒T=mω2l.......(1)Also, Tcosθ=mg.......(2)∴ ω2lcosθ=g⇒ω=glcosθ∴ Time period of rotation, T1=2π10=2π2×cos60o10sec=2π110sec