A small steel ball falls through a liquid at a constant speed of  1 ms-1 .If the steel ball is pulled upwards with a force equal to twice its effective  weight, how fast will it move upward     (in ms-1)

at terminal velocity viscous force upward = apparent weight down ward Fv=Apparent wt =Wif it is pulled with double the effective  weight  then upward force is  2w , downward force is w    and viscous force will be downward direction w so that net force will be zero hence for same viscous force velocity will be also same but upward