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Q.

A smaller block of 2kg is placed over a larger block of 5kg. Coefficient of friction between blocks is 0.3 and large block is on smooth surface. A force of 2N is applied on lower block, then work done  by friction on upper block in 3 seconds is

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answer is 0.735J.

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Detailed Solution

fl=μm1g=0.3×2×10=6NF
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