A smooth block is released at rest on a 45° incline and then slides a distance d. The time taken to slide is n times as much to slide on rough incline than on a smooth incline. The coefficient of friction is
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a
μs=1−1n2
b
μs=1−1n2
c
μk=1−1n2
d
μk=1−1n2
answer is C.
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Detailed Solution
See fig.Let t be the time taken by the block to cover a distance d.Then using the formula, s=ut+(1/2)g′t2, we get d=12g sin45∘t2 …(1)∵u=0 and g′=gsin45∘Let t' be the time taken for rough plane.Then d=12gsin45∘−μkcos45∘t′2 or d=12gsin45∘−μkcos45∘(nt)2 …(2)Equating equations (1) and (2), we getsin45∘=sin45∘−μkcos45∘n2or 12×1n2=12−μk2 or μk=1−1n2.