Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A smooth curved surface of height 10m is ended horizontally. A spring of force constant 200 Nm-1 is fixed at the horizontal end as shown in figure. When an object of mass 10 g is released from the top, it travels along the curved path and collides with the spring. Then, the maximum compression in the spring is (Take, g=10 ms-2)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

10 m

b

0.1 m

c

1 m

d

0.01 m

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let the maximum compression in the spring be x. From law of conservation of energy, mgh=12kx2              10×10-3×10×10=12×200×x2⇒                                     x2=10×10-3=10-2⇒                                     x=1100=110m=0.1mThus, compression in the spring is 0.1m.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring